beam: add Trie (prefix tree) with tests

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beam committed 2026-10-25 20:12:34 +00:00
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import random
from trie import Trie
def test_basic():
t = Trie()
for w in ["cat", "car", "card", "dog", ""]:
t.insert(w)
assert t.search("cat")
assert t.search("")
assert t.search("card")
assert not t.search("ca")
assert t.starts_with("ca")
assert not t.starts_with("z")
assert sorted(t.words_with_prefix("ca")) == ["car", "card", "cat"]
assert t.count_prefix("ca") == 3
assert len(t) == 5
def test_delete():
t = Trie()
for w in ["car", "card", "care"]:
t.insert(w)
assert t.delete("car")
assert not t.search("car")
assert t.search("card")
assert t.search("care")
assert t.starts_with("car")
assert not t.delete("car")
# delete shared prefix leaf should prune
t.delete("card"); t.delete("care")
assert not t.starts_with("car")
def test_duplicate_insert():
t = Trie()
t.insert("abc"); t.insert("abc")
assert t.search("abc")
t.delete("abc")
assert not t.search("abc") # one delete removes word entirely (count not tracked per multiplicity)
# acceptable: delete removes end flag
def test_random_vs_bruteforce():
rng = random.Random(123)
words = []
alphabet = "ab"
for _ in range(200):
w = "".join(rng.choice(alphabet) for _ in range(rng.randint(0, 5)))
words.append(w)
t = Trie()
s = set()
for w in words:
t.insert(w); s.add(w)
for w in set(words):
assert t.search(w) == (w in s)
# delete half
to_del = list(s)[: len(s) // 2]
for w in to_del:
assert t.delete(w)
s.discard(w)
for w in set(words):
assert t.search(w) == (w in s), (w, t.search(w), w in s)
# prefix enumeration matches
for p in ["", "a", "b", "aa", "ab"]:
got = set(t.words_with_prefix(p))
exp = {w for w in s if w.startswith(p)}
assert got == exp, (p, got, exp)
if __name__ == "__main__":
test_basic(); test_duplicate_insert(); test_delete(); test_random_vs_bruteforce()
print("ALL OK")
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"""Prefix trie with insert/search/startsWith/delete and prefix enumeration.
Correctness notes:
- delete only removes nodes that are not shared by other words; marks end-of-word
flags rather than blindly removing.
- search is exact word match; starts_with is prefix match.
- words_with_prefix returns sorted list (deterministic).
- Empty string is a valid word if inserted.
"""
from __future__ import annotations
class _Node:
__slots__ = ("children", "is_end", "count")
def __init__(self):
self.children: dict[str, "_Node"] = {}
self.is_end: bool = False
self.count: int = 0 # number of words passing through this node
class Trie:
def __init__(self):
self.root = _Node()
def insert(self, word: str) -> None:
node = self.root
node.count += 1
for ch in word:
node = node.children.setdefault(ch, _Node())
node.count += 1
node.is_end = True
def search(self, word: str) -> bool:
node = self._walk(word)
return node is not None and node.is_end
def starts_with(self, prefix: str) -> bool:
return self._walk(prefix) is not None
def _walk(self, s: str):
node = self.root
for ch in s:
if ch not in node.children:
return None
node = node.children[ch]
return node
def delete(self, word: str) -> bool:
# returns True if word was present and removed
node = self._walk(word)
if node is None or not node.is_end:
return False
# decrement counts along path; prune empty branches
self._remove(self.root, word, 0)
return True
def _remove(self, node: _Node, word: str, depth: int) -> bool:
if depth == len(word):
if not node.is_end:
return False
node.is_end = False
return len(node.children) == 0
ch = word[depth]
child = node.children.get(ch)
if child is None:
return False
should_delete_child = self._remove(child, word, depth + 1)
if should_delete_child:
del node.children[ch]
return (not node.is_end) and len(node.children) == 0
return False
def words_with_prefix(self, prefix: str) -> list[str]:
node = self._walk(prefix)
if node is None:
return []
out: list[str] = []
self._collect(node, prefix, out)
return sorted(out)
def _collect(self, node: _Node, prefix: str, out: list[str]) -> None:
if node.is_end:
out.append(prefix)
for ch in sorted(node.children):
self._collect(node.children[ch], prefix + ch, out)
def count_prefix(self, prefix: str) -> int:
node = self._walk(prefix)
return node.count if node is not None else 0
def __len__(self) -> int:
# number of distinct words
out = [0]
def dfs(n):
if n.is_end:
out[0] += 1
for c in n.children.values():
dfs(c)
dfs(self.root)
return out[0]
if __name__ == "__main__":
t = Trie()
for w in ["cat", "car", "card", "dog"]:
t.insert(w)
print(t.search("car"), t.starts_with("ca"), t.words_with_prefix("ca"))
t.delete("car")
print(t.search("car"), t.search("card"))