beam: add Levenshtein edit distance with two-row DP and verified tests

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beam committed 2026-10-25 05:59:25 +00:00
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"""Levenshtein edit distance with an optimal two-row DP.
Provides:
edit_distance(a, b) -> int
ops(a, b) -> list of operations ('=', 'S', 'D', 'I') aligned to a
(substitution/deletion/insertion)
Correctness: dp[i][j] = min edits to transform a[:i] into b[:j].
Recurrence:
dp[0][j] = j
dp[i][0] = i
dp[i][j] = min(
dp[i-1][j] + 1, # delete a[i-1]
dp[i][j-1] + 1, # insert b[j-1]
dp[i-1][j-1] + (a[i-1] != b[j-1]) # match/substitute
)
Space optimized to two rows: O(min(n,m)) memory, O(n*m) time.
"""
from __future__ import annotations
def edit_distance(a: str, b: str) -> int:
if a == b:
return 0
if not a:
return len(b)
if not b:
return len(a)
# ensure b is the shorter to minimize memory
if len(a) < len(b):
a, b = b, a
# now a is longer-or-equal; iterate over b columns
prev = list(range(len(b) + 1))
for i, ca in enumerate(a, 1):
cur = [i] + [0] * len(b)
for j, cb in enumerate(b, 1):
cost = 0 if ca == cb else 1
cur[j] = min(prev[j] + 1, cur[j - 1] + 1, prev[j - 1] + cost)
prev = cur
return prev[-1]
def ops(a: str, b: str) -> list[str]:
"""Return operation tags aligned to characters of a: '=' match, 'S' sub,
'D' delete (a char absent in b), plus trailing 'I' inserts for extra b chars.
Reconstructs via backtracking on full table (O(n*m) memory) for clarity."""
n, m = len(a), len(b)
# full table
dp = [[0] * (m + 1) for _ in range(n + 1)]
for i in range(n + 1):
dp[i][0] = i
for j in range(m + 1):
dp[0][j] = j
for i in range(1, n + 1):
for j in range(1, m + 1):
cost = 0 if a[i - 1] == b[j - 1] else 1
dp[i][j] = min(dp[i - 1][j] + 1, dp[i][j - 1] + 1, dp[i - 1][j - 1] + cost)
# backtrack
res: list[str] = []
i, j = n, m
while i > 0 or j > 0:
if i > 0 and j > 0:
cost = 0 if a[i - 1] == b[j - 1] else 1
if dp[i][j] == dp[i - 1][j - 1] + cost:
res.append("=" if cost == 0 else "S")
i -= 1
j -= 1
continue
if i > 0 and dp[i][j] == dp[i - 1][j] + 1:
res.append("D")
i -= 1
continue
# insert
res.append("I")
j -= 1
res.reverse()
# inserts that occur after all of a are already represented as trailing I's
return res
if __name__ == "__main__":
import sys
if len(sys.argv) < 3:
print("usage: levenshtein.py STR1 STR2", file=sys.stderr)
sys.exit(2)
print(edit_distance(sys.argv[1], sys.argv[2]))
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import random, string
from levenshtein import edit_distance, ops
def brute(a, b):
n, m = len(a), len(b)
dp = [[0]*(m+1) for _ in range(n+1)]
for i in range(n+1): dp[i][0]=i
for j in range(m+1): dp[0][j]=j
for i in range(1,n+1):
for j in range(1,m+1):
c = 0 if a[i-1]==b[j-1] else 1
dp[i][j]=min(dp[i-1][j]+1, dp[i][j-1]+1, dp[i-1][j-1]+c)
return dp[n][m]
def test_known():
cases = [("kitten","sitting",3),("","abc",3),("abc","",3),
("flaw","lawn",2),("same","same",0),("a","b",1),
("","",-0 if False else 0)]
for a,b,e in cases:
assert edit_distance(a,b)==e, (a,b,edit_distance(a,b),e)
def test_random_vs_brute():
rng = random.Random(42)
alpha = "ab"
for _ in range(2000):
la = rng.randint(0,8); lb = rng.randint(0,8)
a = "".join(rng.choice(alpha) for _ in range(la))
b = "".join(rng.choice(alpha) for _ in range(lb))
assert edit_distance(a,b)==brute(a,b), (a,b)
def test_ops_roundtrip():
rng = random.Random(7)
for _ in range(500):
a = "".join(rng.choice("ab") for _ in range(rng.randint(0,6)))
b = "".join(rng.choice("ab") for _ in range(rng.randint(0,6)))
o = ops(a,b)
# apply ops to a -> should yield b
out = []
i = 0 # index into a
j = 0 # index into b
for tag in o:
if tag == "=":
assert a[i] == b[j]
out.append(a[i]); i += 1; j += 1
elif tag == "S":
out.append(b[j]); i += 1; j += 1
elif tag == "D":
i += 1
elif tag == "I":
# need current b char; find next unconsumed b
out.append(b[j]); j += 1
assert "".join(out) == b, (a,b,o,"".join(out))
edits = sum(1 for t in o if t in ("S","D","I"))
assert edits == edit_distance(a,b), (a,b,edits,edit_distance(a,b))
if __name__ == "__main__":
test_known(); test_random_vs_brute(); test_ops_roundtrip()
print("ALL OK")